Given the following reaction: h2so4+2lioh=li2so4+2h20, what mass of water is produced from 19 g of sulfuric acid?

Hi,

To solve the question, first of all we will find out the no. of moles of H2SO4 in  19 g of sulfuric acid.

As we know:

              No . of moles = Mass/ Molar mass

              No. of moles= 19 g/98.08 g

               No. of moles= 0.1937

Now we know the no of moles of H2SO4 that will react with 2LiOH. We also know the  molar equivalence of H2SO4 , and 2LiOH that will react.

So, the  water that will be produced will be 2H2O and 1 Li2SO4 when H2SO4 that will react with 2LiOH.

                          0.1937 x 2x 18.01

                                 =6.977

                                  =6.98

Therefore, approximately 6.98 grams of water will be produced from 19 g of sulfuric acid.

Hope it helps!