Glucose (C6H12O6) undergoes combustion with molecular oxygen to form carbon dioxide and water. How many O2 molecules are needed for each molecule of glucose

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Ответ:

Nathaliasmiles

15.05.2023

Chemistry

Thus the volume of the balloon at that new location is $4.65\times 10^4L$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

P_1 = initial pressure of gas = 0.995 atm

P_2 = final pressure of gas = 0.720 atm

V_1 = initial volume of gas = $3.93\times 10^4L$

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 32.0^oC=273+32.0=305.0K

T_2 = final temperature of gas = -11.7^oC=273-11.7=261.3K

Now put all the given values in the above equation, we get:

$\frac{0.995\times 3.93\times 10^4}{305.0}=\frac{0.720\times V_2}{261.3}$

$V_2=4.65\times 10^4L$

Thus the volume of the balloon at that new location is $4.65\times 10^4L$

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