Chemistry: Group a used 5.00 moles of styrene and 0.0010 moles of benzoyl peroxide while group b used the same amount of benzoyl peroxide as group a but used only 1.50 moles styrene. what would the average molecular weight of each group s polymer sample be

10 molesExplanation:set it up as a proportion450 kL/20 moles = 225 kL/ x molesCross multiply to solve for x....

Group a used 5.00 moles of styrene and 0.0010 moles

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12.03.2022

Answer : Average molecular weight of group A = 104.0276 g

Average molecular weight of group B = 104.0920 g

Solution : Given, Moles of group A styrene = 5 moles

Moles of group A benzoyl peroxide = 0.0010 moles

Moles of group B styrene = 1.5 moles

Moles of group B benzoyl peroxide = 0.0010 moles

Molecular mass of styrene = 104 g/mole

Molecular mass of benzoyl peroxide = 242.23 g/mol

Formula used : Average molar mass = Total mass / Total moles

For group A,

Average molar mass of group A = $\frac{\text{Total mass of group A}}{\text{Total moles of group A}}$

= $\frac{\left ( 5\times 104 \right )+\left ( 0.0010\times 242.23 \right )}{5+0.0010}$

= $\frac{520+0.24223}{5.0010}$

= $\frac{520.24223}{5.0010}$

= 104.0276 g

Average molar mass of group A = 104.0276 g

For group B,

Average molar mass of group B = $\frac{\text{Total mass of group B}}{\text{Total moles of group B}}$

= $\frac{\left ( 1.5\times 104 \right )+\left ( 0.0010\times 242.23 \right )}{1.5+0.0010}$

= $\frac{156+0.24223}{1.5010}$

= $\frac{156.24223}{1.5010}$

= 104.0920 g

Average molar mass of group B = 104.0920 g

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