HCl + NaOH → NaCl + H2O

1. If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the theoretical yield of the experiment?

2. If 30 g of HCl is reacted with excess NaOH, and 10 g of NaCl is produced, what is the percent yield of the experiment?

Answer and Explanation:

Equation: HCl + NaOH → NaCl + H2O

Calculation of Part 1.

Number of moles of HCl = 30 divided by 36.46 = 0.823 moles.

Number of moles of NaCI that are produced = 0.823 moles

Theoretical weight of product formed = 0.823 multiply 58.44 = 48.08 gms.

Thus, theoretical yield = 48.08 gms.

Calculation of Part 2.

Yield of NaCI = 10 grams.

Percent yield is equal to 10 divided by 48.08 multiply with 100

= 20.8%

Explanation: potassium (Na) has one electron in outer shell

And it donates it easily and can even reduce

Hydrogen gas from water. An alkaline solution containing

Hydroxide ions (OH-) is then formed