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destineenikole175

destineenikole175

05.05.2020 •

Chemistry

HELP
DUMB
SMART AT OTHER THINGS
PLZ

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Ответ:

joel4676

25.01.2022

sorry

you're not dumb

Explanation:

please don't be mad

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Ответ:

Jasoncookies23

14.06.2021

K_a for the acid is $2.7\times 10^{-4}$

Explanation:

$C_9H_7O_4H\rightarrow H^+C_9H_7O_4^-$

c 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.313 M and = 2.031

$(\alpha)=0.030$

$[H^+]=c\times \alpha$

$[H^+]=0.500\times 0.030=0.015$

Also pH=-log[H^+]

2.031=-log[H^+]

[H^+]=0.009

[ $[H^+]=c\alpha$

$c\alpha=0.009$

Putting in the values we get:

$K_a=\frac{(0.009)^2}{(0.313-0.009)}$

$K_a=\frac{(0.009)^2}{(0.304)}=2.7\times 10^{-4}$

K_a for the acid is $2.7\times 10^{-4}$

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