HELP How many moles of Ag (silver) contain 4.49 x 1023 atoms Ag?
27.0 mol
0.746E23 mol
0.746 mol
0.746E24 mol

C, 0.746 mol Ag.

1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag

0.333 atm

Explanation:

Step 1: Given data

Step 2: Convert 30.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30.0 + 273.15 = 303.2 K

Step 3: Calculate the final pressure of the gas

If we assume ideal behavior and constant volume, we can calculate the final pressure od the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 0.370 atm × 273.15 K/303.2 K = 0.333 atm