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1. A 100. g samle of water absorbs how many Joules of energy as its temperature is changed from
35.0 C to 60.0 C. (water s = 4.184 J/g C)
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Ответ:
10460J
Explanation:
Given parameters:
Mass of water sample = 100g
Initial temperature = 35°C
Final temperature = 60°C
Unknown:
Amount of energy absorbed by water = ?
Solution:
The amount of energy absorbed by water is mathematically expressed below;
H = m C ΔT
H is the amount of energy
m is the mass
C is the specific heat capacity of water = 4.184J/g°C
ΔT = 60°C - 35°C = 25°C
Now insert the parameters and solve;
H = 100 x 4.184 x 25 = 10460J
Ответ: