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dianaherrera041
31.05.2021 •
Chemistry
How many atoms are present in 14 g of iron
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Ответ:
1.51 × 10²³ atoms
Explanation:
First, we convert 14g of iron (Fe) to moles using the formula below:
mole = mass ÷ molar mass
Molar mass of Fe = 55.85g/mol
mole = 14g ÷ 55.85g/mol
mole = 0.251mol
The number of atoms in 0.251 mol of Fe is calculated as follows:
number of atoms = n × nA
Where;
n = number of moles
nA = Avagadros number (6.02 × 10²³)
number of atoms = 0.251 × 6.02 × 10²³
number of atoms = 1.51 × 10²³ atoms.
Ответ:
All the atoms in its structure are linked to each other by strong covalent bonds. The atoms are joined to each other in a regular arrangement, forming a giant covalent structure. There is no set number of atoms joined together in this type of structure.
Explanation: