Chemistry: How many electrons are contained in an ion formed from an atom of na?

How many electrons are contained in an ion formed

Ответ:

lbelle

27.04.2023

The freezing point of water will be lowered 3°C

Explanation:

Remember that molality is generally the standard for calculating the concentration, between molarity and molality. In this question we have to apply molality, given the units as moles and kilograms.

We can start by receiving the molality of this solution through the following formula...

$\mathrm{m}=\mathrm{(mass}\mathrm{/molar\:mass)} * (1000/\mathrm{mass\:of\:solvent)},$

$\mathrm{m} =\mathrm{(400.0 g / 62.07 g/mol) * (1000 / 4000.0 g)},$

$\mathrm{m} = (400/62.07) * (1000 / 4000) = \left(\frac{400}{62.07}\right)\left(\frac{1000}{4000}\right) = \frac{1000}{620.7} = 1.61108\dots\mathrm{m}$

Now we can determine how much the freezing point of water will be lowered, given that the freezing-point depression constant for water is Kf= –1.86°C/m. Remember that " Kf " is the final temperature, so to determine how much the temperature of the water will decrease, we can note the change in temperature...

$\mathrm{change\:in\:temperature} = ( - 1.86\mathrm{C/m})(1.61\mathrm{m}) = - 1.86 * 1.61 = -2.9946$

$-2.9946 = \mathrm{About\:-3C}$

Hence the freezing point of water will be lowered 3°C.

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How many electrons are contained in an ion formed from an atom of na?

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