Chemistry: how many fold difference is the hydrogen ion concentration if the ph is 6.7 is increased to 8.7

how many fold difference is the hydrogen ion concentration

Ответ:

natalie2sheffield

12.03.2022

Chemistry

pH of the solution is calculated using the following formula:

$pH=-log{[H^{+}]}$

Here, $[H^{+}]$ is concentration of hydrogen ion.

Initial value of pH is 6.7, calculate concentration of hydrogen ion from this as follows:

$[H^{+}]=10^{-pH}$

Putting the value,

$[H^{+}]=10^{-6.7}=1.9952\times 10^{-7}$

Thus, initial concentration of hydrogen ion is $1.9952\times 10^{-7}$ .

Now, final pH value is 8.7, calculate concentration of hydrogen ion as follows:

$[H^{+}]=10^{-8.7}=1.9952\times 10^{-9}$

Thus, final concentration of hydrogen ion is $1.9952\times 10^{-9}$ .

The ratio of final to initial value will be:

$\frac{1.9952\times 10^{-9}}{1.9952\times 10^{-7}}=\frac{1}{100}$

Thus, if pH increases from 6.7 to 8.7, concentration of hydrogen ion becomes $\frac{1}{100}$ of the initial value.

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Ответ:

lclaudettecarte4720

06.11.2021

Chemistry

Criteria for the implementation of drinking water:

where drinking water comes from and its qualitytechnical interventionhygiene education for communityregulations, laws and managementsroutine water sampling and analysis

Limitations:

availability of resources (human, finance, equipment)geographical conditionsclimatological conditionscommunity and authority and transport infrastructure

Explanation:

For more information:

https://www.who.int/water_sanitation_health/dwq/gdwqvol32ed.pdf?ua=1https://www3.epa.gov/region1/eco/drinkwater/your_drinkwater_source.html

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"how many fold difference is the hydrogen ion concentration if the ph is 6.7 is increased to 8.7"

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