How many grams of N2 are required to react with 4.2 moles of Mg in the following process? 3 Mg + N2 → Mg3N2? (Mg = 24.3 g/mol, N = 14.0 g/mol)

x = 0.45*28/3 = 4.2 g

Explanation:

showing work

N2 = 28 g/mole

3Mg + N2 → Mg3N2

3moles .. 28 g

0.45 moles .. x

x = 0.45*28/3 = 4.2 g (answer)

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

= heat of combustion of benzoic acid

= heat energy released to water

= heat energy released to the calorimeter

Therefore,

1.056*26.42 = [0.987*4.18 + 6.66]( - 23.32)

27.8995 = [4.12566+6.660]( - 23.32)

( - 23.32) = 27.8995/10.7857 = 2.587

= 23.32 + 2.587 = 25.907°C