How many grams of nacl is present in .75 l of a 1 m solution of nacl?
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Ответ:
The answer to your question is 43.9 g of NaCl
Explanation:
Data
Grams of NaCl = ?
Volume = 0.75 L
Molarity = 1 M
Number of moles = ?
Formula
Solve for number of moles
Number of moles = Molarity x volume
Substitution
Number of moles = 1 x 0.75
= 0.75
Molecular weight of NaCl = 23 + 35.5 = 58.5
Calculate the grams of NaCl using proportions
58.5 g of NaCl ---------------- 1 mol
x ---------------- 0.75 moles
x = (0.75 x 58.5) / 1
x = 43.9 g of NaCl
Ответ:
1. Carbon-12
2. Nitrogen-13
3. Carbon-13