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jaydahh4059
29.12.2019 •
Chemistry
How many grams of naoh are needed to prepare 2.0 l of a 1.5 m naoh solution?
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Ответ:
120 grams
Explanation:
Data:
Volume = V= 2 L
Molarity = 1.5 M
Molecular masses:
Na = 23, O= 16, H=1
Total molecular mass =M= 23+16+1 = 40
mass = m = ?
To find the mass we need to find moles from molarity formula:
Molarity = n/V
n= Molarity x V
= 1.5 x 2
n= 3 moles
Now we can find mass:
number of moles = given mass / molecular mass
n = m/M
m= n x M
= 3 x 40
m = 120 grams
Ответ:
120 grams of NaOH
Explanation:
This can be solved by using Unit Conversion.
Let n = # grams of NaOH needed to prepare 2.0 L of a 1.5 M NaOH solution.
Known variables
V = 2.0 L
[NaOH] = 1.5 mol/L
Molecular Weight of NaOH = 39.997 g/mol
n = 2.0 L x (1.5 mol/L) x (39.997 g NaOH/ mol) = 119.991 grams
rounding to two significant figures
n = 120 grams of NaOH
Ответ: