How many grams of pb are contained in a mixture of 0.135 kg each of pbcl(oh) and pb2cl2co3?

Mass of lead in is 107.74 g and mass of lead in is 103.6 g

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of PbCl(OH) = 0.135 kg = 135 g   (Conversion factor:  1 kg = 1000 g)

Molar mass of PbCl(OH) = 259.66 g/mol

Putting values in equation 1, we get:

In 1 mole of PbCl(OH), 1 mole of lead, 1 mole of chlorine, 1 mole of hydrogen and 1 mole of oxygen atoms are present.

Moles of lead =

Calculating the mass of lead in PbCl(OH) by using equation 1, we get:

Molar mass of lead atom = 207.2 g/mol

Moles of lead atom = 0.52 moles

Putting values in equation 1, we get:

Mass of lead atom = 107.74 g

Given mass of = 0.135 kg = 135 g

Molar mass of = 545.3 g/mol

Putting values in equation 1, we get:

In 1 mole of , 2 moles of lead, 2 moles of chlorine, 1 mole of carbon and 3 moles of oxygen atoms are present.

Moles of lead =

Calculating the mass of lead in by using equation 1, we get:

Molar mass of lead atom = 207.2 g/mol

Moles of lead atom = 0.50 moles

Putting values in equation 1, we get:

Mass of lead atom = 103.6 g

Hence, mass of lead in is 107.74 g and mass of lead in is 103.6 g

When 1.20 mole of ammonia reacts, 1.8 moles of water are produced.

Explanation:

The balanced reaction is:

4 NH₃(g) + 5 O₂(g) → 4 NO (g) + 6 H₂O

By stoichiometry of the reaction, the following amounts of moles participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 4 moles of ammonia produce 6 moles of water, 1.2 moles of ammonia will produce how many moles of water?

moles of water= 1.8 moles

When 1.20 mole of ammonia reacts, 1.8 moles of water are produced.