How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

If there are 14 different scenarios that can happen (Blue 1-5, Green 1-6, Red 1-3), and 9 of them are not blue, there is a 9/14 chance that the first pick is not blue. to get percentages, you divide 9 by 14 to get 0.64, or 64 percent chance at not picking blue.