How many milliliters of a stock solution of 6.80 MM HNO3HNO3 would you have to use to prepare 0.110 LL of 0.470 MM HNO3HNO3 ?
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Ответ:
We need 7.60 mililiters of the stock solution
Explanation:
Step 1: Data given
Molarity stock solution = 6.80 M HNO3
Volume of the new solution = 0.110 L
Molarity of the new solution = 0.470M
Step 2: Calculate volume needed
C1*V1 = C2*V2
⇒ with C1 = the concentration of stock = 6.80 M
⇒ with V1 = volume of stock solution = TO BE DETERMINED
⇒ with C2 = the new concentration = 0.470 M
⇒ with V2 = the new volume = 0.110 L
6.80 M * V1 = 0.470 * 0.110
V1 = 0.00760 L = 7.60 mL
We need 7.60 mililiters of the stock solution
Ответ: