Chemistry: How many molecules are present in 3.09 mol of silicon dioxide, SiO2

The correct answer is Option B.Explanation:To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:We are given:Putting values in above equation, we get:To calculate pH of the solution, we use the equation:pH is defined as negative logarithm of hydrogen ion or hydronium ion concentration. It is basically defined as the power of hydronium ions in a solution.pH of the solution = 2Putting values in above equation, we get:Hence,...

How many molecules are present in 3.09 mol of

Ответ:

wrivera32802

09.02.2022

Chemistry

There are 1.86 x 10²⁴ molecules of Silicon dioxide, SiO₂

Further explanation

The mole is the number of particles(molecules, atoms, ions) contained in a substance

Moles can also be determined from the amount of substance mass and its molar mass

1 mol = 6.02.10²³ particles

Can be formulated

$\tt \boxed{\bold{N=n\times No}}$

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Given

3.09 mol of Silicon dioxide, SiO₂

n=mol=3.09

Number of molecules :

$\tt N=n\times No\\\\N=3.09\times 6.02\times 10^{23}\\\\N=\boxed{\bold{1.86\times 10^{24}~molecules}}}$

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Ответ:

Taylor129

07.09.2022

Chemistry

The correct answer is Option B.

Explanation:

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=1\times 10^{-12}M$

Putting values in above equation, we get:

$pOH=-\log(1\times 10^{-12})\\\\pOH=12$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH=14-12=2$

pH is defined as negative logarithm of hydrogen ion or hydronium ion concentration. It is basically defined as the power of hydronium ions in a solution.

$pH=-\log[H_3O^+]$