Chemistry: How many molecules of ethane are present in 64.28 liters of ethane gas (c2h6) at stp

How many molecules of ethane are present in 64.28

Ответ:

HernanJe6

11.01.2022

Use the Ideal Gas Law
PV = nRT

$(1.00atm)(64.28L) = n(.08206L*atm*mol^{-1}*K^{-1})(273.15K)$
n = 2.8677moles
$2.8677mol* \frac{6.022*10^{23}molecules}{1mol}$
$= 1.727*10^{24}molecules$
That was using Avogadro's number :)

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Ответ:

lyn94

30.04.2020

Chemistry

1 st,4,5,6 describe valid orbitals

HOPE IT HELPS

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How many molecules of ethane are present in 64.28 liters of ethane gas (c2h6) at stp

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