How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?

A. 0.07 moles
B. 0.15 moles
C. 0.34 moles
D. 15

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

The correct answer is

Aluminum, boron, and gallium are likely together in one group because they have the same number of valence electrons, and carbon and germanium are likely together in another group because they have the same number of valence electrons.

This is the only one that makes sense after reviewing the data. Hopefully this helps! Feel free to mark as brainliest!