How many moles of chloride ions are in 0.2510 g of aluminum chloride?

1.882 x 10^(-3) moles aluminum chloride has a formula of AlCl3. So let's calculate the molar mass of AlCl3 atomic mass of Al = 26.982 atomic mass of Cl = 35.453 molar mass of AlCl3 = 26.982 + 3 * 35.453 = 26.982 + 106.359 = 133.341 We have 0.2510 grams of AlCl3, so divide that by the molar mass of AlCl3, giving 0.2510 / 133.341 = 0.001882 moles = 1.882 x 10^(-3) moles

100 liters because 4 x 100 = 400
hope this helps!!