How many moles of H30* or OH must you add to a liter of strong acid solution to adjust its pH from 3.27 to 3.77? Assume a negligible volume change.

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Ответ:

Riohxncho

29.04.2022

Chemistry

a) Mass of solid W crystallized out 0°C is 141.564 g

b) 91.92% is the percent recovery.

Explanation:

The solubility of solid W in water at 100°C = 21.3 g/100 mL

Volume of water at 100C required to dissolve 154.0 g of W: x

$\frac{154.0 g}{x}=\frac{21.3 g}{100 mL}$

$x=\frac{154.0 g\times 100 mL}{21.3 g}=723.0 mL$

723.0 mL of water will dissolve 154.0 grams of solid W.

The solubility of solid W in water at 0°C = 1.72 g/100 mL

Mass of W soluble in 723.00 mL of water at 0°C = m

$\frac{m}{723.0 mL}=\frac{1.72 g}{100 mL}$

$m=\frac{1.72 g\times 723.0 mL}{100 mL}=12.436 g$

a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g

b) Percent recovery of solid at 0°C:

$\frac{141.564 g}{154.0 g}\times 100=91.92\%$

91.92% is the percent recovery.

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