mmmmm96061
02.04.2020 •
Chemistry
How many moles of HBr are present in 250 ml of a 0.15 M HBr solution?
Solved
Show answers
More tips
- F Family and Home Is It Worth Spoiling a Child?...
- S Society and Politics Will Japan become Russia s Military Enemy?...
- P Philosophy Is Everything We Strive for Eventually Achieved and Destroyed?...
- S Society and Politics Understanding Politics and Its Role in the Development of Civilization...
- P Philosophy Why Did God Create Man and Place Him in Obscurity?...
- S Society and Politics Skoptsy: Who They Are and How They Perform Castration?...
- O Other Childhood Fears: What Many of Us Experienced...
- P Philosophy What is Something for you?...
- H Health and Medicine Why Do Humans Have One Heart?...
- P Philosophy Unbelievable stories of encounters with otherworldly forces...
Answers on questions: Chemistry
- C Computers and Technology Write a computer program to calculate the linear and parabolic rate constants for wet and dry oxidation for temperatures of 950, 1000, 1050, 1100, 1150, and 1200 c. assume 100...
- M Mathematics Se consideră numerele a=5k; b=10 puterea n; c=300 puterea m; k,n,m apartine mulțimi nr naturale.pentru ce valori ale lui k,n,m numerele date sunt divizibile cu : a)2 b)3 c)4 d)9...
- M Mathematics 2×(4×2-10)³ How do you simplify powers in this? ...
- B Biology What are some common cell organelles...
Ответ:
0.0375 moles HBr
Explanation:
we are given;
Molarity of HBr solution as 0.15 MVolume of the solution as 250 mLWe are required to determine the number of moles;
We need to know that;
Molarity = Moles ÷ Volume
Therefore;
Moles of HBr = Molarity of HBr solution × Volume of solution
Thus;
Moles of HBr = 0.15 M × 0.25 L
= 0.0375 Moles
Thus, the number of moles of HBr solute is 0.0375 moles
Ответ:
Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)
The reaction between hept-3-yne and bromine produces trans-3,4-dibromo-3-heptene.
The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.
In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.
The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.