Pomskis2341
08.05.2020 •
Chemistry
How many moles of magnesium nitrate are in 6.35 grams of magnesium nitrate?
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Ответ:
0.0428 moles
Explanation:
6.35 g Mg(NO3)2 ×
6.35 g / 148.32 g
0.0428 moles
Ответ:
The tempearture of 11.2 L of CO is .
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Thus the tempearture of 11.2 L of CO is , pressure remaining constant.