How many moles of oh− ions are present in 388.3 ml of 0.094 m calcium hydroxide? enter to 4 decimal places?

The kinetic energy is 3917.57J/mol

Explanation:

The kinetic energy (K.E.) of a body is the energy possess by the body while on motion

K.E is given by 1/2xM

Where M= mass in Kg = 32.5/1000

M= 0.0325kg

V = velocity in m/s = 491m/s

Substituting these values in the formual

K.E = 1/2MV^{2}

K. E = ½ x 0.0325kgx 491 m/s x 491 m/s

K.E = 3917.57kg/ / mol

But  kg/ = Joule

Thus kinetic energy, K.E = 3917.57kg/ / mol