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kaleighlong959
23.11.2020 •
Chemistry
How many moles of oxygen are required for the combustion of 35.5 g of Magnesium Mg+O2-->MgO Please balance
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Ответ:
0.74 moles of oxygen are required for combustion
Explanation:
Given data:
Number of moles of oxygen required = ?
Mass of Mg = 35.5 g
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 35.5 g/ 24 g/mol
Number of moles = 1.48 mol
Now we will compare the moles of Mg with oxygen.
Mg : O₂
2 : 1
1.48 : 1/2×1.48 = 0.74 mol
0.74 moles of oxygen are required for combustion.
Ответ:
0.24 dm
Explanation: