How much energy is released when 75g of liquid water is reduced from 65c to 0c and completely freezes?

Q = 20377.5 Joules

Explanation:

Given the following data;

Mass = 75g

Initial temperature = 65°C

Final temperature = 0°C

Specific heat capacity of water = 4.18 J/g°C.

To find the quantity of heat released;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have;

Q = 20377.5 Joules

mass of HCN=7934.14Kg, mass of H2O=2812.5

Explanation:

Since there is 100% yield,it means all the reactants are converted in to products

2 NH3 (g) + 3 O2 (g) + 2 CH4 (g) → 2 HCN (g) + 6 H2O (g)

molar mass of O2=16

molar mass of HCN=27.02

molar mass of H2O=18

Applying mole ratio

no of mole =mass/molar mass

since ammonia(NH3)  is converted in to Hydrogen cyanide(HCN)

no of mole of ammonia =no of mole of hydeogen cyanide

1:1

mass of NH3/molar mass of  NH3=mass of HCN/molar mas of HCN

by making :mass of HCN the subject,

mass of HCN=5000×27.02/17.031

Mass of HCN=7934.14kg

applying the same mole ratio

Oxygen is converted in to water

no of mole of O2=2×no of mole of H2O

Mass of O2/molar mass of O2=2×mass of H2O/molar mass of H2O

by making mass of H2O the subject

mass of H2O=5000×18/32

=2815.5kg