How much heat is released when 30 g of water at 96°c cools to 25°c?
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Ответ:
from ,
Heat=mass×specific heatt capacity×temperature change
Heat=30g×1cal(specific heatcapacity of water)×(25-96)
=-2130cal/°C negative mean heat given out
Ответ:
800 g
Explanation:
We can express the decay of I-37 using the formula:
Final Mass = Initial Mass *We input the data:
25 g = Initial Mass *And solve for Initial Mass:
25 g = Initial Mass *Meaning that out 800 grams of I-37, only 25 will remain after 40.35 days.