How much heat is released when 345 g of tin is cooled from 210.0 degrees * C to 0.0 C? (C= 0.220 J/gC)
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Ответ:
18634 joules
Explanation:
The quantity of Heat Energy (Q) released when a heated substance is cooled depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of oil = 345g
C = 0.220 J/g°C
Φ = (Final temperature - Initial temperature)
= 0°C - 220°C = -220°C
Then, Q = MCΦ
Q = 345g x 0.220 J/g°C x -220°C
Q = 18634 joules (note that negative sign will not reflect in answer, because it only indicates that heat was released rather than gained)
Thus, 18634 joules of heat is released
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