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foreignlove1039
27.05.2021 •
Chemistry
How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
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Ответ:
150000 J
General Formulas and Concepts:Chemistry
Thermodynamics
Specific Heat Formula: q = mcΔT
q is heat (in J)m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C or K)Math
Pre-Algebra
Order of Operations: BPEMDAS
to RightExplanation:Step 1: Define
Identify variables
[Given] m = 225 g
[Given] c = 4.184 J/g °C
[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C
[Solve] q
Step 2: Solve for q
Substitute in variables [Specific Heat Formula]: q = (225 g)(4.184 J/g °C)(159.8 °C)Multiply: q = (941.4 J/°C)(159.8 °C)Multiply: q = 150436 JStep 3: Check
Follow sig fig rules and round. We are given 3 sig figs.
150436 J ≈ 150000 J
Topic: AP Chemistry
Unit: Thermodynamics
Book: Pearson AP Chemistry
Ответ:
Mass of Carbon = 12 * 2 = 24
Mass of Hydrogen = 1 * 6 = 6
Ratio of Carbon to Hydrogen = 24/6 = 4
In short, Your Answer would be: 4:1
Hope this helps!