layshjjbradshaw7250
05.08.2019 •
Chemistry
How much solution could be heated to boiling by the heat evolved by the dissolution of 26.5 g of naoh? (for the solution, assume a heat capacity of 4.0 j/g⋅∘c, an initial temperature of 25.0 ∘c, a boiling point of 100.0 ∘c, and a density of 1.05 g/ml.)
Solved
Show answers
More tips
Answers on questions: Chemistry
- C Chemistry [Chemistry] 2CuCl2+4Kl— 2Cul+4KCl+l2 When 753 grams of CuCl2 reacts with 166 grams of Kl, how many moles of KCI are formed ? What’s the limited reaction ?...
- C Chemistry Hi any girl that are 12or 13 and are cute and funny and not fat...
- C Chemistry Puzzle #1- Periodic Table Escape Room About 70 elements had been discovered by the mid-1800s, but until the work of the Russian chemist Dmitri Mendeleev, no one had found...
- C Chemistry PLEASE HELP DUE TODAY you decide to go put for a walk. You walk 8km to the north in 2 hours, then you walk 3km to the south in 1 hour. what is your average speed for...
- C Chemistry 50 POINTS Silver tarnishes when it is exposed to air and light. The density of silver is 10.49 g/cm3, the melting point is 962 degrees C and the boiling point is 2000...
- C Chemistry A. front is where the airmass has stopped...
- C Chemistry Thermal energy is transferring part...
- C Chemistry Determine the molar mass of a gas that has a density of 2.18g / l at 67 degrees * c and 720 mm hg ....
- C Chemistry The amount of water vapor in a given volume of air is...
- C Chemistry Ideal gas (n 2.388 moles) is heated at constant volume from t1 299.5 k to final temperature t2 369.5 k. calculate the work and heat during the process and the change...
Ответ:
94.642 mL
Explanation:
Given:
Mass of the NaOH, m = 26.5 g
Heat capacity of the solution, C = 4.0 J/g°C
Initial temperature = 25.0° C
Density = 1.05 g/mL
Now,
Molat mass of NaOH = 40 g/mol
Lattice energy of (NaOH) = 887 kJ/mol
The heat of hydration (NaOH) = 932 kJ/mol.
Thus,
The heat of dissolution of 1 mol of NaOH = 887 kJ/mol - 932 kJ/mol = -45 kJ/mol.
Number of moles of (NaOH), n = (26.5 g) / (40 g/mol) = 0.6625 mol.
Now, the change in temperature, ΔT = 100°C - 25°C = 75°C.
Thus,
the heat of dissolution of 0.6625 mol of NaOH, Q = -45 kJ/mol × 0.6625 mol = - 29.8125 kJ. = - 29812.5 J
Also
Q = m'CΔT
on substituting the values in the above formula, we get
- 29812.5 J = m' × 4 J/g·°C × 75°C.
m' = mass of the solution
or
m' = 99.375 g
m' = 90 g of solution.
Now,
Density = Mass / Volume
on substituting the values, we get
1.05g/mL = 99.375 g / Volume
or
Volume of the solution = 94.642 mL
Ответ: