How much water should be added to 12 ml of 13% alcohol solution to reduce the concentration to 6%?
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Ответ:
We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%
Explanation:
Step 1: Data given
Original solution has 12 mL of 13% alcohol
New volume has a concentration of 6%
Step 2: Determine how much pure alcohol you have in the solution.
0.13 * 12ml = 1.56 ml pure alcohol.
Step 3: Calculate ratio alcohol: total in volume
1.56 ml / 12 ml = .013
Step 4: add water to the total solution and set the desired percentage
1.56 ml / (12ml + x) = 0.06
1.56 = 0.06 (12 + x)
1.56 = 0.72 + 0.06x
0.84 = 0.06x
x = 14
We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%
Ответ:
= Sqrt(2 × 44)
= Sqrt(2 × 4 × 11)
= Sqrt(2 × 2 × 2 × 11)