How much work (in j) is involved in a chemical reaction if the volume decreases from 5.00 to 1.26 l against a constant pressure of 0.857 atm?
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Ответ:
V₂ - V₁ = 1.26 - 5 L = - 3.74 L = - 3.74 x 10⁻³ m³
The constant pressure is
p = 0.857 atm = 0.857*101325 Pa = 86836 Pa
By definition, the work done is
The work involved is 324.8 J
Ответ:
hoped I helped =)