How to determine the limiting reagent in CH3COOH+NaHCO3-CH3CONa+H2o+CO2​

The volume of the balloon after 38.0 hours is 99.55 L

Explanation:

Given;

volume of helium in the weather balloon, V = 110 L

initial mole of the gas, n = 4 mol

the rate leak of the gas, dn/dt = 10 mmol/hr

After 38.0 hours, the moles of the gas lost = 38hr x 10 x 10⁻³ mol/hr = 0.38 mol

the moles of the gas lost = 0.38 mol

Number of moles of helium in balloon after 38.0 hours = 4 mol - 0.38 mol

                                                                                            = 3.62 mol

Volume of helium in balloon after 38.0 hours ;

Therefore, the volume of the balloon after 38.0 hours is 99.55 L