![jessicajamah3289](/avatars/5232.jpg)
jessicajamah3289
30.11.2019 •
Chemistry
Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight of h-3 sample be?
Solved
Show answers
More tips
- A Animals and plants Уход за джунгариками: полезные советы и рекомендации...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- S Sport How to Choose Tennis Rackets?...
- H Health and Medicine AKDS Vaccination: Ensure Your Child s Safety...
- H Health and Medicine Naskol ko Opasen Ukus Kleshcha i Kak Ego Raspoznat...
- C Computers and Internet How to Delete Your Account on Odnoklassniki...
- H Health and Medicine What to Do When Your Jaw Locks Up?...
- G Goods and services What Are the Most Popular Services?...
- P Philosophy How did the concept of module arise in computer science?...
Answers on questions: Chemistry
- M Mathematics Plz me brainliest to whoever answers first....
- M Mathematics Which side lengths do not represent a 30-60°-90° triangle? 1 2 2 b) V2, Vo, 212 5 513 10 2° 2 d) 3, 313,6...
- M Mathematics Find the surface area of the figure below. SA = 1/2 pl + B 15 in 18 in 18 in...
- M Mathematics A car travelling at v kilometers per hour will need a stopping distance, d, in meters without skidding that can be modelled by the function d=0.0067v2+0.15v. Determine the speed...
Ответ:
The final mass of sample is 1.3 g.
Explanation:
Given data:
Half life of H-3 = 12.32 years
Amount left for 15.0 years = 3.02 g
Final amount = ?
Solution:
First all we will calculate the decay constant.
t₁/₂ = ln² /k
t₁/₂ =12.32 years
12.32 y = ln² /k
k = ln²/12.32 y
k = 0.05626 y⁻¹
Now we will find the original amount:
ln (A°/A) = Kt
ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y
ln (3.02 g/ A) = 0.8439
3.02 g/ A = e⁰°⁸⁴³⁹
3.02 g/ A = 2.33
A = 3.02 g/ 2.33
A = 1.3 g
The final mass of sample is 1.3 g.
Ответ:
that one is the nucleus
Explanation: