Hydrogen iodide is not produced by the same method is for hydrogen chloride why with reaction
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Ответ:
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Ответ:
Answer : The correct option is, (A)![C_{6}H_{12}O_6](/tpl/images/0464/7306/c31f7.png)
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
As we are given that the empirical formula of a compound is
and the molar mass of compound is, 180.2 gram/mol.
The empirical mass of
= 1(12) + 2(1) + 1(16) = 30 g/eq
Molecular formula =![(CH_2O)_n=(CH_2O)_6=C_{6}H_{12}O_6](/tpl/images/0464/7306/ce529.png)
Thus, the molecular formula of the compound will be,![C_{6}H_{12}O_6](/tpl/images/0464/7306/c31f7.png)