kayleebueno
13.09.2019 •
Chemistry
Hydrogen reacts with sodium to produce solid sodium hydride. a reaction mixture contains 6.75 g na and 3.03 g hydrogen. which reactant is limiting?
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Ответ:
Na
Explanation:
To find the limiting reactant we must first write the balanced chemical reaction. It must be correctly balanced so that we can find the proper mole ratios.
2 Na + H₂ → 2 NaH
After this we will convert our measurements to moles. For mass we do this by dividing by the molar mass.
6.75g ÷ 22.99 = 0.294mol Na
3.03g ÷ 2.02 = 1.50mol H₂
Now that we have the moles of each of the reactants, we can multiply them by their mole ratio with a reactant.
0.294mol Na × = 0.294mol NaH
1.50mol H₂ × 2/1 = 3.00mol NaH
Na is our limiting reagent because it makes the smaller amount of moles.
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