yazmine912
18.03.2021 •
Chemistry
I am a circuit with one path. If one of my bulbs goes out all of the other bulbs will go out. One switch will control all of my bulbs. What type of circuit am I?
Series circuit
Parallel circuit
Open current
Alternating current
Solved
Show answers
More tips
- F Food and Cooking How to Choose the Right Olive Oil: A Comprehensive Guide...
- P Philosophy Is Everything We Strive for Eventually Achieved and Destroyed?...
- S Society and Politics Understanding Politics and Its Role in the Development of Civilization...
- P Philosophy Why Did God Create Man and Place Him in Obscurity?...
- S Society and Politics Skoptsy: Who They Are and How They Perform Castration?...
- O Other Childhood Fears: What Many of Us Experienced...
- P Philosophy What is Something for you?...
- H Health and Medicine Why Do Humans Have One Heart?...
- P Philosophy Unbelievable stories of encounters with otherworldly forces...
- O Other How to Accidentally Get a Rare Coin with Your Change and How to Know Its Value?...
Answers on questions: Chemistry
- C Chemistry Covalent compounds: mastery test select the correct answer what is formed when atoms join together with a covalent bond? a. an ion b. a molecule c. a neutral atom d. a noble gas...
- H Health In addition to body composition cardiovascular endurance muscle strength and flexibility what other element is a component of physical fitness...
- M Mathematics HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP...
- E English Which sentence contains a split infinitive? a.young children seem to thoroughly enjoy playing with soap bubbles and shaving cream. b.it is important to give children opportunities...
Ответ:
Ответ:
Ответ:
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).
6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
[Ca2+] = 0.00065 M
The maximum concentration of [Ca2+] is 0.00065 M, and you have 0.0010 M Ca(OH)2, so you’ll end up with 0.00065 M Ca2+ in solution.