I need 5 free branlilys Who every get then i will - id58250001, josecano2

Question

Chemistry: I need 5 free branlilys Who every get then i will send then back 10

josecano2 · Accepted Answer

NH₃ is the limiting reactant.Theoretical yield = 120 kg% yield = 72.9 %

Explanation:

2NH₃ (aq) + CO₂ (aq) → CH₄N₂O (aq) + H₂O (l)

First we convert the given masses of reactants to moles, using their respective molar masses:

68.2 kg NH₃ ÷ 17 kg/kmol = 4.01 kmol NH₃105 kg CO₂ ÷ 44 kg/kmol = 2.39 kmol CO₂

2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.

We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:

4.01 kmol NH₃ * $\frac{1kmolCH_4N_2O}{2kmolNH_3}$ = 2.00 kmol CH₄N₂O

We convert that amount to kg:

2.00 kmol CH₄N₂O * 60 kg/kmol = 120 kg CH₄N₂O

Finally we calculate the percent yield:

87.5 kg / 120 kg * 100% = 72.9 %

I need 5 free branlilys
Who every get then i will send then back 10