I need help on this, It’s due today. Please, anybody

1 = 252g, 2 = 2mL, 3 = 1.5mL, 4 = 3g, 5 = 225g, 6 = 0.92g/mL, 7 = 0.75g/mL, 8 = 0.71g/mL, 9 = 1.9mL, 10= 1.11mL, 11 = 76.9g

Explanation:

This problem is testing how well you can move around the equation D = m/v where D = Density (g/mL), m= mass of sample (g), v = volume of sample (mL).

The ratio of mass of sulfur atom to mass of oxygen atom in sulfur dioxide is 1: 1.

Explanation:

Law of constant proportion states that In a chemical substance the elements are always present in definite proportions by mass. This law is also known as 'Law of definite proportions '.

Mass of 1 atom of sulphur = 32 g

Mass of 1 atom of oxygen = 16 g

Mass of 2 atoms of oxygen =

In formation of , 1 atom of sulfur combines with 2 atoms of oxygen and thus the mass ratio will be 32: 32= 1:1 .

Thus the ratio of mass of sulfur atom to mass of oxygen atom in sulfur dioxide is 1: 1.