I spent an hour but I got nothing ;-;
Draw diagrams with ions shown in the products and reactions for the following reactions.
11. calcium hydroxide(aq) + iron(III)chloride(aq)->
12. rubidium fluoride(aq) + copper(II) sulfate(aq)
I have the full reactions written down so they are solved (I think)
Solved
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Ответ:
182mL
Explanation:
Given parameters:
Molarity of solution = 3.11M
New volume = 232mL = 0.232dm³
New molarity = 2.44M
Unknown:
Volume of original solution = ?
Solution:
We know the full information about the new solution we want to obtain. From this, we should find the number of moles.
Using the number of moles, we can find the original volume.
Molarity =![\frac{number of moles }{volume}](/tpl/images/0569/2635/abf61.png)
New number of moles = molarity x volume = 2.44 x 0.232
= 0.57moles
The original volume will be;
Volume =
=
= 0.182dm³ or 182mL