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treseanthegreat
28.01.2020 •
Chemistry
Identify the limiting and excess reactants when 1.00 g of zinc reacts with 150 ml of 0.250m pb(no3)2. how many grams of lead are formed in this single replacement reaction
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Ответ:
Zn + Pb(NO₃)₂ → Pb + Zn(NO₃)₂
The moles of lead are calculated using:
moles = concentration x volume
moles = 0.25 x 0.15
moles = 0.0375
The moles of zinc are: 1 / 65 = 0.015
We see from the equation that equimolar quantities of zinc and lead should be present. Therefore, lead is in excess and zinc is the limiting reactant.
Ответ:
The pair that consists of a base and its conjugate acid in that order.![NH_3/NH_4^+](/tpl/images/0553/7439/e8643.png)
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.