Identify two ways in which space exploration has influenced florida's economy and culture

Space exploration has changed Florida's economy, in a way that without space exploration, our technology would still be stagnant and thus, space exploration enabled Florida to become an active participant in boosting and creating technology for various sectors. Also, space exploration has provided many jobs in cape Canaveral.

1- 114.54 g.

2- 78.32 g.

Explanation:

Q1:

The balanced equation of the reaction is:

F₂ + 2NaCl → Cl₂ + 2NaF.

It is clear that 1.0 mole of F₂ reacts with 2.0 moles of NaCl to produce 1.0 mole of Cl₂ and 2.0 moles of NaF.We can calculate the no. of moles of F₂ (15.0 liters at 280.0 K and 1.50 atm) using the ideal gas law:

PV = nRT,

where, P is the pressure of the gas (P = 1.0 atm),

V is the volume of the gas (V = 15.0 L),

n is the no. of moles of the gas (n = ??? mole),

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas (T = 280.0 K).

∴ n = PV/RT = (1.5 atm)(15.0 L) / (0.082 L/atm/mol.K)(280.0 K) = 0.98 mol.

We can get the no. of moles of NaCl  reacted with 0.98 mol of F₂.

Using cross multiplication:

1.0 mole of F₂ reacts with → 2.0 moles of NaCl, from the stichiometry.

0.98 mole of F₂ reacts with → ??? moles of NaCl.

∴ The no, of moles of reacted NaCl = (2.0 mole)(0.98 mole)/(1.0 mole) = 1.96 mol.

Now, we can get the mass of NaCl that reacted with F₂ at 280.0 K and 1.50 atm:

∴ The mass of NaCl = n x molar mass of NaCl = (1.96 mol)(58.44 g/mol) = 114.54 g.

Q2:

STP conditions means that P = 1.0 atm and T = 273.0 K.We can calculate the no. of moles of F₂ (15.0 liters at 273.0 K and 1.0 atm) using the ideal gas law: PV = nRT,

∴ n = PV/RT = (1.0 atm)(15.0 L) / (0.082 L/atm/mol.K)(273.0 K) = 0.67 mol.

We can get the no. of moles of NaCl  reacted with 0.67 mol of F₂.

Using cross multiplication:

1.0 mole of F₂ reacts with → 2.0 moles of NaCl, from the stichiometry.

0.67 mole of F₂ reacts with → ??? moles of NaCl.

∴ The no, of moles of reacted NaCl = (2.0 mole)(0.67 mole)/(1.0 mole) = 1.34 mol.

Now, we can get the mass of NaCl that reacted with F₂ at 280.0 K and 1.50 atm:

∴ The mass of NaCl = n x molar mass of NaCl = (1.34 mol)(58.44 g/mol) = 78.32 g.