meowmeowcow
06.07.2019 •
Chemistry
If 1.00 mol of argon is placed in a 0.500-l container at 27.0 degree c , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der waals equation)? for argon, a=1.345(l2⋅atm)/mol2 and b=0.03219l/mol. express your answer to two significant figures and include the appropriate units.
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Ответ:
2.0 atm is the difference between the ideal pressure and the real pressure.
Explanation:
If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C
Moles of argon = n = 1.00 mol
Volume of the container,V = 0.500 L
Ideal pressure of the gas = P
Temperature of the gas,T = 27 °C = 300.15 K[/tex]
Using ideal gas equation:
Vander wall's of equation of gases:
The real pressure of the gas=
For argon:
b=0.03219 L/mol.
Difference :
2.0 atm is the difference between the ideal pressure and the real pressure.
Ответ:
Hello!
Determine the empirical formula of a compound containing 47.37 grams of carbon, 10.59 grams of hydrogen, and 42.04 grams of oxygen.
In an experiment, the molar mass of the compound was determined to be 228.276 g/mol. What is the molecular formula of the compound?
We have the following data:Carbon (C) ≈ 12 a.m.u (g/mol)
Hydrogen (H) ≈ 1 a.m.u (g/mol)
Oxygen (O) ≈ 16 a.m.u (g/mol)
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)C: 47.37 g
H: 10.59 g
O: 42.04 g
The values (in g) will be converted into quantity of substance (number of mols), dividing by molecular weight (g / mol) each of the values, we will see:We realize that the values found above are not integers, so we divide these values by the smallest of them, so that the proportion does not change, let us see:convert number of atomic radio into whole number
2 * (1.5 : 4 : 1)
= 3 : 8 : 2 ← whole number of atomic radio
C = 3
H = 8
O = 2
Thus, the empirical formula found for the compound will be:We are going to find the Molar Mass (MM) of the Empirical Formula (EF), let's see:if: C3H8O2
C = 3*(12 a.m.u) = 36 a.m.u
H = 8*(1 a.m.u) = 8 a.m.u
O = 2*(16 a.m.u) = 32 a.m.u
Knowing that the Molar Mass of the Molecular Formula is 228.276 (in g/mol) and that the Molar Mass of the Empirical Formula is 76 (in g/mol), then we will find the number of terms (n) for the molecular formula of the compound, let us see:The Molecular Formula is the Empirical Formula times the number of terms (n), then, we have:Answers:
The empirical formula: C3H8O2
The molecular formula: C9H24O6