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jesuscruzm2020
23.09.2019 •
Chemistry
If 140. mg of fluorine-18 is shipped at 8: 00 a.m., how many milligrams of the radioisotope are still active when the sample arrives at the radiology laboratory at 1: 30 p.m.
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Ответ:
To answer the question we need to know the half-life of fluorine for reference we have chlorine half-life as 110. The fraction of chlorine remaining would be given by![0.5^n](/tpl/images/0254/1591/8f663.png)
Explanation:
Here we know and is known as the number of Half-life that have elapsed during this process Now we are giving the time of start as 8 a.m. and time of finishing at 1:30 p.m., so the time between is 5 ½ hours. Which on converting in minutes will give 330 minutes.
So Half Life elapsed would be given by =![330/110=3](/tpl/images/0254/1591/08838.png)
Hence the amount remaining would be =![0.5 ^3 \times 125 =15.625](/tpl/images/0254/1591/800de.png)
Ответ:
17.4 mg of the radioisotope are still active when the sample arrives at the radiology laboratory at 1:30 P.M.
Explanation:
Half-life of F-18 is found to be 109.7 minutes
Rate constant
t = time taken = 5 hours 30 minutes = 330 minutes
[A] is the final quantity
Plugging the values and solving for [A]
[A] = 17.4mg is the Answer
Ответ:
E = MC
yeet yoink yt