Chemistry: If 28.0 grams of pb(no3)2 react with 18.0 grams of nai, what mass of pbi2 can be produced? pb(no3)2 + nai → pbi2 + nano3

Transitional elements are usually described as elements of the d block. oxygen is not in the d block, and hence is not a transitional element....

If 28.0 grams of pb(no3)2 react with 18.0 grams - id28032180602153, gracepiechowiak

Ответ:

alondrahernande3

11.03.2022

Chemistry

- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

$Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3$

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

$28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})$

= 39.0gPbI_2

$18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})$

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2 , so the answer is, 27.7 g of PbI_2 are produced.

0,0(0 оценок)

If 28.0 grams of pb(no3)2 react with 18.0 grams of nai, what mass of pbi2 can be produced? pb(no3)2 + nai → pbi2 + nano3

Ответ:

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question