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aliyahlknox881
28.12.2019 •
Chemistry
If 3.60 ml of vinegar needs 43.0 ml of 0.130 m naoh to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.30 qt sample of this vinegar?
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Ответ:
There is 114.53 grams of acetic acid in 1.30 qt of sample
Explanation:
Step 1: Data given
Volume of vinegar = 3.60 mL
Volume of 0.130 M NaOH = 43.0 mL
1 qt = 0.946353 L
1.30 qt = 1.23026 L = 1230 mL
Step 2: Calculate moles of NaOH
Moles NaOH = molarity * volume
Moles NaOH = 0.130 M * 0.043 L
Moles NaOH = 0.00559 moles
Step 3: Calculate concentration of vinegar
Concentration = moles / volume
Concentration = 0.00559/ 0.00360 L
Concentration = 1.55 M
Step 4: Calculate mass of acetic acid in 1.30 qt sample
1.30 qt * 0.946353 L * 1.55 M *60.06 g/mol =114.53 grams
There is 114.53 grams of acetic acid in 1.30 qt of sample
Ответ:
Energy exists in a field.
Explanation:
Electrical field, magnetic field, and gravitational field.
A and B are wrong otherwise the law of conservation of energy would be violated