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sepdentalcare8774
03.11.2020 •
Chemistry
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the water layer. Assuming waterand chloroform are immiscible, and all salicylate is unionized, whatis the distribution coefficient (chloroform/water) of salicylate in the chloroform-water solvent system
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Ответ:
Distribution coefficient: 4.79
Explanation:
Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:
Distribution coefficient: Concentration in chloroform / Concentration in Water
Concentration in water: 2.59mg / 30mL = 0.08633mg/mL
Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL
Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL
Distribution coefficient: 4.79Ответ:
97.0%m/m es la concentración de la solución
Explanation:
El porcentaje masa/masa (%m/m) se define como 100 veces el radio entre la masa de soluto (300g de HCl) y la masa de la solución. Para hallar la masa de la solución debemos hallar la masa del agua (Solvente) haciendo uso de la ecuación del volumen de un cono. Con el volumen del cono podemos hallar la masa del agua haciendo uso de la densidad, así:
Volumen:
Volumen Cono = π*r²*h / 3
Donde r es el radio = 0.300m
h la altura = 5m
Volumen = π*(5m)²*0.300m / 3
7.85m³
Masa Agua:
7.85m³ * (1.2g / m³) = 9.42g Agua
Masa solución:
300g HCl + 9.42g Agua = 309.42g Solución
%m/m:
300g HCl / 309.42g * 100 =
97.0%m/m es la concentración de la solución