If 32.146g of mgso4 is added to enough water to make 100.00ml solution, what is the molarity of mgsoa? 1) 2.6706 m 2) 3.7445m 3) 0.037445 4) 0.0026706 m 5) 3869.4 m

Explanation:

Hello,

At first, the moles of magnesium sulfate must be computed by knowing that its molecular mass has a value of  120.366 g/mol:

Now, by knowing that the volume must be in L, it turns out into 0.10000 L, thus:

Best regards.

The first thing we have to do is change and state all the units so that we can use our ideal gas law equation ().

650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.

P = 86kPa

T = 15°C + 273K = 288K

R (Gas constant) = 8.31 kj/mol  

Molar mass of Ammonia () = (1 x 3) + (14) = 17g/mol

n (moles) = 3.34 mol

V = ?

Rearrange the equation to solve for Volume:

Substitute the values inside:

V =

Therefore 93 L of volume is occupied by the ammonia gas.