If 35.5 grams of calcium oxide react with excess water, how many grams of calcium hydroxide can be formed?
CaO + H2O - Ca(OH)2

Mass of Ca(OH)2= 46.916 g

Given

Reaction

CaO + H2O - Ca(OH)2

Required

mass of Ca(OH)2

Solution

Mol of CaO :

= mass : MW

= 35.5 g : 56 g/mol

= 0.634

From the equation , mol ratio CaO : Ca(OH)2 = 1 : 1, so mol Ca(OH)2 = 0.634

Mass Ca(OH)2 :

= mol x MW

= 0.634 x 74

= 46.916 g

reciprocal pascal(Pa−1m) :⋅ kg−1⋅s2

joule per square metre(J/m2) :- kg⋅s−2

kilogram square metre (kg⋅m2) :- m2⋅kg

newton metre second per kilogram(N⋅m⋅s/kg):-m2⋅s−1

Explanation:

Hope it'll help!