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randallmatthew6124
19.02.2020 •
Chemistry
If 5.50 mol of HCl and 3.00 mol of O2 react according to the following equation, how many grams of water will form?
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Ответ:
49.52 g of H₂O
Explanation:
The balance chemical equation for given reaction is as follow;
4 HCl + O₂ → 2 H₂O + 2 Cl₂
Step 1: Find out Limiting reagent as;
According to balance equation,
4 moles of HCl reacted with = 1 mole of O₂
So,
5.50 moles of HCl will react with = X moles of O₂
Solving for X,
X = 5.50 mol × 1 mol / 4 mol
X = 1.375 moles of O₂
This means to completely consume 5.5 moles of HCl we will need 1.375 moles of O₂ while, we are provided with 3.0 moles of O₂ which is in excess hence, the limiting reagent in this problem is HCl and it will control the yield of products.
Step 2: Calculate Moles of H₂O produced;
According to balance equation,
4 moles of HCl produced = 2 moles of H₂O
So,
5.50 moles of HCl will react with = X moles of H₂O
Solving for X,
X = 5.50 mol × 2 mol / 4 mol
X = 2.75 moles of H₂O
Step 3: Calculate Mass of H₂O as;
Mass = Moles × M.Mass
Mass = 2.75 mol × 18.01 g/mol
Mass = 49.52 g of H₂O
Ответ:
The answer is below
Explanation:
one gallon of gasoline produces 9.50 kg of carbon.
The total number of cars = 40 million
Distance covered by each car = 7930 miles
Consumption rate of the cars per miles traveled is 23.6 miles per gallon.
Hence the annual gasoline consumption by all the cars in the United States of America = (total number of cars × Distance covered by each car) ÷ Consumption rate of the cars per miles
annual gasoline consumption by all the cars = (40000000 × 7930 miles) ÷ 23.6 miles/gallon = `1.344067797 × 10¹⁰ gallons
1.344067797 × 10¹⁰ gallons =![1.344067797*10^{10}\ gallons *\frac{9.50\ kg}{1\ gallon} =1.276864407*10^{11}\ kg\ of \ carbon\ dioxide](/tpl/images/0776/5016/f75cc.png)